Ravi travels from City A to City B. If Ravi drives his car at $$\frac 23$$​ of his normal speed, then he reaches City B 47 minutes late. Find the time (in minutes) that Ravi would have taken to travel from City A to City B if he drove at his normal speed.

Correct option is B

Given: 

Ravi travels from City A to City B. If Ravi drives his car at $$\frac 23$$​ of his normal speed, then he reaches City B 47 minutes late.

Concept Used:

The time taken to travel is inversely proportional to the speed, meaning that if speed decreases, time increases.

Solution: 
Let normal time = t minutes.
New time = 3t/2
Extra time = 3t/2 - t = 47
t/2 = 47 → t = 94
Normal travel time = 94 minutes.

Alternate Solution: ​

For constant distance; 

Speed $$\propto \frac1{Time}$$

Speed ratio = 2    :     3

Time ratio = 3     :     2

3- 2 = 47 min.

1 unit = 47 min.

2 unit = 94 min. 

time taken by normal speed = 2 × 47 = 94 min.