Ravi can complete a task in D + 12 hours, and Rohit can complete the same task in D + 24 hours. If Rohit's efficiency is 25% less than Ravi’s, then find the value of D.
Information Given:
Ravi can complete a task in D + 12 hours.
Rohit can complete the same task in D + 24 hours.
Rohit's efficiency is 25% less than Ravi’s.
Formulas Used:
Efficiency and time being inversely proportional
Efficiency =
Basic Explanation:
Ravi’s efficiency =
Rohit’s efficiency =
ATQ,
D+12 = 0.75D + 18
0.25D = 6
D = 24
Exam Hall Method:
English
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