Rishi can finish $$\frac{1}{4}^{th}$$​ of a certain work in 26 days. Rakesh can finish $$\frac{9}{20}^{th}$$​ of the same work in 18 days. Rustum can finish 2/3 of the same work in 48 days. Who will complete the work first?

Correct option is C

Given:
Rishi completes 1/4th work in 26 days.
Rakesh completes 9/20th work in 18 days.
Rustum completes 2/3rd work in 48 days.
Formula Used:
Total time taken = $$\frac{Time\ for\ partial\ work}{Fraction\ of\ work\ done}$$​​
Solution:
Calculate the total time each person takes to complete the entire work.
Time taken by Rishi:
26 × 4 = 104 days
Time taken by Rakesh:
18 × $$\frac{20}{9}$$​ = 2 × 20 = 40 days
Time taken by Rustum:
48 × $$\frac{3}{2}$$​ = 24 × 3 = 72 days
Comparing the total days required:
Rakesh takes the minimum time (40 days). Thus, Rakesh will complete the work first.
Final Answer
So the correct answer is (c)