Suppose, Total work = 10 units
=> Efficiency of P = 1 unit/day
Work done by P in 4 days = 1 x 4 = 4 units
=> Remaining work = 10-4= 6 units
Let efficiency of Q be x
=9x=6
=>x= 2/3
Total efficiency of P and Q = 1 + 2/3 = 5/3 units/day
Required Time =10/5/3 =6 days
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