100 men have provisions for 26 days. If 50 men have left, for how many days the same provisions would last for the remaining men?

Correct option is C

Given
Initial men (M_1) = 100
Initial days (D_1) = 26
Men who left = 50
Formula Used
​$$M_1 \times D_1 = M_2 \times D_2$$​​
Solution
Remaining men $$(M_2) = 100 - 50 = 50$$​​
Let the required number of days be $$D_2.$$​​
​$$100 \times 26 = 50 \times D_2 \\D_2 = \frac{100 \times 26}{50}\\D_2 = 2 \times 26 = 52 days\\$$​​
Final Answer
So the correct answer is (c)
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