Given: MI alone: 14 days, M2 alone: 70 days, M1 + M2 + M3 together: 7 days
Formula Used: Work done per day = 1/Days for each worker
Solution:
Work done by M1 in 1 day = 1/14,
M2 in 1 day = 1/70,
M1 + M2 + M3 in 1 day = 1/7
Let work done by M3 in 1 day = 1/M3 days
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60 Mins English English20 Questions40 Marks12 Mins English English80 Questions160 Marks60 Mins EnglishWorking together A, B and C can complete a certain work in 40 days. B and C together can complete thesame work in 60 days. B is 25% more efficient than A. In how many days will C alone complete 40% ofthe same work?
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