Manish travels from City A to City B. If Manish drives at $$\frac 13$$​of his normal speed, he reaches 36 minutes late. Find the time taken at normal speed.

Correct option is D

Given:
Reduced speed = $$\frac 13$$​ of normal speed
Delay = 36 minutes
Formula Used:
$$\text{Time} \propto \frac{1}{\text{Speed}}$$​
Solution:
Let normal time = t minutes
At 1/3 speed, time = 3t
Delay = 36 min
 3t − t = 36
2t = 36
t = 18 minutes