Janaki leaves her home every day at 7:55 a.m and reaches office at 9:25 a.m. However, one day she left her home at 7:55 a.m. but reached office at 09:20:30 a.m.

Which of the statements below support the information provided above?

Statement 1: Janaki travelled $$\frac{3}{10}$$​ of the distance at $$\frac{6}{7}$$​ of her usual speed and the rest of the distance at $$\frac{7}{6}$$​ of her usual speed.

Statement 2: Janaki travelled $$\frac{5}{8}$$​ of the distance at $$\frac{5}{4}$$​ of her usual speed and the rest of the distance at $$\frac{5}{6}$$​ of her usual speed.

Statement 3: Janaki travelled $$\frac{7}{9}$$​ of the distance at $$\frac{5}{6}$$​ of her usual speed and the rest of the distance at $$\frac{20}{3}$$​ of her usual speed.

Correct option is C

Given:

Usual time = 7:55 AM to 9:25 AM = 1 hour 30 minutes = 90 minutes
That day, she took 7:55 AM to 9:20:30 AM = 1 hour 25 minutes 30 seconds = 85.5 minutes
So, she saved 4.5 minutes (90 – 85.5 = 4.5 min).
Thus, her time decreased by 4.5 minutes compared to usual.

Solution:

We now have to check which statements cause this early arrival.

Let’s analyze each statement one-by-one carefully: