Correct option is CGiven:x2+1x2=10x^2+\frac{1}{x^2}=10x2+x21=10, x4+1x4x^4+\frac{1}{x^4}x4+x41Formula Used:To find x4+1x4, we use the identity:x4+1x4=(x2+1x2)2−2\text{To find } x^4 + \frac{1}{x^4}, \text{ we use the identity:} \\x^4 + \frac{1}{x^4} = \left(x^2 + \frac{1}{x^2}\right)^2 - 2To find x4+x41, we use the identity:x4+x41=(x2+x21)2−2Solution:(x2+1x2)2=102=100Now,x4+1x4=100−2=98\left(x^2 + \frac{1}{x^2}\right)^2 = 10^2 = 100 \\\text{Now,} \\x^4 + \frac{1}{x^4} = 100 - 2 = 98(x2+x21)2=102=100Now,x4+x41=100−2=98Final Answer:(c) 98