Correct option is A
Given:
The average of 6 positive integers = 45
The difference between the largest and smallest integers = 18
Formula Used:
Sum of integers =
Solution:
Let the six numbers be N₁, N₂, N₃, N₄, N₅, N₆
Sum of all the six numbers = 45 × 6 = 270
Let the smallest integer be N₁, and the largest integer be N₆
According to given condition:
N₆ = N₁ + 18
N₁ + N₂ + N₃ + N₄ + N₅ + N₆ = 270
N₁ + N₂ + N₃ + N₄ + N₅ + N₁ + 18 = 270
To the minimum value of N₁, we should keep all the numbers equal to Largest Number = N₁ + 18.
N₁ + N₁ + 18 + N₁ + 18 + N₁ + 18 + N₁ + 18 + N₁ + 18 = 270
6N₁ + 90 = 270
6N₁ = 180
N₁ = 30
Minimum Value of N₁ = 30
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