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If tan A = ⅔ , then what is the value of the following (5 sin² A-2 cos² A)÷(15 sin² A+3 cos²A)
Question

If tan A = ⅔ , then what is the value of the following
(5 sin² A-2 cos² A)÷(15 sin² A+3 cos²A)

A.

21/47

B.

2/87

C.

2/5

D.

3/77

Correct option is B

Given: 
tanA=23\tan A = \frac{2}{3} 
Expression; (5 sin² A-2 cos² A)÷(15 sin² A+3 cos²A)  
Concept Used: 
for a right angle triangle; 
tanA=PerpendicularBase\tan A = \frac{ \text{Perpendicular}}{\text{Base}} 
sinA=PerpendicularHypotenuse\sin A = \frac{\text{Perpendicular}}{\text{Hypotenuse}} 
cosA=BaseHypotenuse\cos A = \frac{\text{Base}}{\text{Hypotenuse}} 
Pythagorus theorem: 
(Hypotenuse)2=(Perpendicular)2+(Base)2(Hypotenuse)^2 = (Perpendicular)^2 + ( Base)^2 
Solution:

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