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    If tan A = ⅔ , then what is the value of the following (5 sin² A-2 cos² A)÷(15 sin² A+3 cos²A)
    Question

    If tan A = ⅔ , then what is the value of the following
    (5 sin² A-2 cos² A)÷(15 sin² A+3 cos²A)

    A.

    21/47

    B.

    2/87

    C.

    2/5

    D.

    3/77

    Correct option is B

    Given: 
    tanA=23\tan A = \frac{2}{3} 
    Expression; (5 sin² A-2 cos² A)÷(15 sin² A+3 cos²A)  
    Concept Used: 
    for a right angle triangle; 
    tanA=PerpendicularBase\tan A = \frac{ \text{Perpendicular}}{\text{Base}} 
    sinA=PerpendicularHypotenuse\sin A = \frac{\text{Perpendicular}}{\text{Hypotenuse}} 
    cosA=BaseHypotenuse\cos A = \frac{\text{Base}}{\text{Hypotenuse}} 
    Pythagorus theorem: 
    (Hypotenuse)2=(Perpendicular)2+(Base)2(Hypotenuse)^2 = (Perpendicular)^2 + ( Base)^2 
    Solution:

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