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If tan θ = −125-\frac{12}{5}−512​​, then the value of sin θ is:
Question

If tan θ = 125-\frac{12}{5}​, then the value of sin θ is:

A.

1213\sqrt\frac{12}{13}​​

B.

1213\frac{\sqrt{12}}{13}​​

C.

1213-\frac{12}{13}​​

D.

1215-\frac{12}{15}​​

Correct option is C

Given:

tanθ=125\tan \theta = \frac{-12}{5}​​

Concept Used:​​

tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta}​​

Given:

tanθ=sinθcosθ=125\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{-12}{5}​​

let's consider the opposite side to be -12 and the adjacent side to be 5 (negative sign indicates the angle is in the second or fourth quadrant).

Using the Pythagorean theorem:

Hypotenuse=(12)2+52=144+25=169=13\text{Hypotenuse} = \sqrt{(-12)^2 + 5^2} = \sqrt{144 + 25} = \sqrt{169} = 13​​

sinθ=1213,cosθ=513\sin \theta = \frac{-12}{13}, \quad \cos \theta = \frac{5}{13}​​

sinθ=1213\sin \theta = \frac{-12}{13}​​

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