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If sin 2A = cos 75°, then the smallest positive value of A is:
Question

If sin 2A = cos 75°, then the smallest positive value of A is:

A.

7.5°

B.

30°

C.

15°

D.

75°

Correct option is A

Given:
sin 2A = cos 75 75^\circ​​

Formula Used:

sin (90θ)90^\circ-\theta) =cosθ\theta

Solution:

sin2A=cos75 2A=9075=15 A=152=7.5\sin 2A = \cos 75^\circ \\ \ \\ 2A = 90^\circ - 75^\circ = 15^\circ \\ \ \\A = \frac{15^\circ}{2} = 7.5^\circ

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