If p = (0.001) + 3(0.1) (0.99) + (0.3) (98.01) + (9.9) (98.01), then find the value of$$\frac p {25}$$​

Correct option is D

Given:
p = (0.001) + 3(0.1)(0.99) + (0.3)(98.01) + (9.9)(98.01)
Solution:
p = (0.001) + 3(0.1)(0.99) + (0.3)(98.01) + (9.9)(98.01)
=> p = 0.001 + 3 × 0.1 × 0.99 + 0.3 × 98.01 + 9.9 × 98.01
=> p = 0.001 + 0.297 + 29.403 + 970.299
=> p = 0.001 + 0.297 + 29.403 + 970.299
=> p = 1000
=> $$\frac{p}{25} = \frac{1000}{25}$$​ = 40