What is the value of (0.02³ + 0.004³) ÷ (0.2³ + 0.04³)?

Correct option is D

​Given :

​$$(0.02^3 + 0.004^3) \div (0.2^3 + 0.04^3)$$​​
Solution:

$$\frac{(0.02)^3+(0.004)^3}{(0.2)^3+(0.04)^3} \\ \ \\=\frac{(0.02)^3\left(1+(0.2)^3\right)}{(0.2)^3\left(1+(0.2)^3\right)}\\ \ \\=\left(\frac{0.02}{0.2}\right)^3\\ \ \\=\left(\frac{1}{10}\right)^3\\ \ \\=\frac{1}{1000} = 0.001$$​

​