What is the value of (0.4×0.4×0.4 + 0.02×0.02×0.02) ÷ (1.2×1.2×1.2 + 0.06×0.06×0.06)?

Correct option is A

Given :

​$$(0.4^3 + 0.02^3)\div(1.2^3 + 0.06^3)$$​​

Solution:

$$\frac{0.4^3+0.02^3}{(3\times0.4)^3+(3\times0.02)^3} \\ \ \\=\frac{0.4^3+0.02^3}{27(0.4^3+0.02^3)}\\ \ \\=\frac{1}{27}$$​​