The value of
 $$\frac{3\times0.03}{0.9}+\frac{0.36\times0.02\times0.4}{0.2\times0.3}-\frac{0.001\times0.8}{0.08}$$​is:

Correct option is B

Given:

​$$\frac{3\times0.03}{0.9}+\frac{0.36\times0.02\times0.4}{0.2\times0.3}-\frac{0.001\times0.8}{0.08}$$​​

Solution:

$$\frac{3\times0.03}{0.9}+\frac{0.36\times0.02\times0.4}{0.2\times0.3}-\frac{0.001\times0.8}{0.08}$$​​

=$$\frac{0.09}{0.9} +\frac{0.00288}{0.06}-\frac{0.0008}{0.08}$$​
= 0.1 + 0.048 - 0.01 = 0.138