If 'M' is the smallest perfect square number, which is exactly divisible by 12, 15 and 18, then find the sum of the digits of the quotient obtained, when M is divided by 25.

Correct option is B

Given:

​'M' is the smallest perfect square number, which is exactly divisible by 12, 15 and 18

Solution:

$$\text{LCM of } (12, 15, 18) = 180$$ 

$$180 = 2\times2\times 3 \times 3 \times 5$$ (Multiply by one 5)

$$180 \times 5 = 900 \text{ is the number}$$ 

$$=\frac{900}{25}= 36$$ 

The sum of the digits of the quotient is $$3 + 6 = 9$$​

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