Given:
cot( A+B).cot(A-B) = 1
Value Used:
Cot(45) =1
Solution:
Let value of B = 0
cot( A+B).cot(A-B) = 1
Put the value of B in equation
cot( A+0).cot(A-0) = 1
(cot(A)) =1
Cot(A)=Cot(45)
A =45
So, Value of cot (2A/3) = cot (90/3)
Cot(30)=
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