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    If cot A=1,sin B=1/√2, then find the value of sin (A+B)-cot (A+B).
    Question

    If cot A=1,sin B=1/√2, then find the value of sin (A+B)-cot (A+B).

    A.

    1-√2

    B.

    1/2

    C.

    0

    D.

    1

    Correct option is D

    Given: ​
    cot A=1, sin B=1/√2, 
    Formula Used: 
    Value of  cot450=1andsin450=12\cot 45^0 = 1 \quad \text{and} \quad \sin 45^0 = \frac{1}{\sqrt{2}} ​
    Solution: 

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