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If cot A=1,sin B=1/√2, then find the value of sin (A+B)-cot (A+B).
Question

If cot A=1,sin B=1/√2, then find the value of sin (A+B)-cot (A+B).

A.

1-√2

B.

1/2

C.

0

D.

1

Correct option is D

Given: ​
cot A=1, sin B=1/√2, 
Formula Used: 
Value of  cot450=1andsin450=12\cot 45^0 = 1 \quad \text{and} \quad \sin 45^0 = \frac{1}{\sqrt{2}} ​
Solution: 

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