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    ​If cot⁡4A+cot⁡2A=1, then find the value of cos⁡4A−3cos⁡2A.\text{If } \cot^4 A + \cot^2 A = 1, \text{ then find the
    Question

    If cot4A+cot2A=1, then find the value of cos4A3cos2A.\text{If } \cot^4 A + \cot^2 A = 1, \text{ then find the value of } \cos^4 A - 3 \cos^2 A.​​

    A.

    -1

    B.

    -2

    C.

    2

    D.

    1

    Correct option is A

    Given:

    cot4A+cot2A=1 \cot^4 A + \cot^2 A = 1

    Solution:

    cot2A(cot2A+1)=1cos2Asin2A×1sin2A=1 cos2A=sin4A\cot^2 A \left( \cot^2 A + 1 \right) = 1\\\frac{\cos^2 A}{\sin^2 A} \times \frac{1}{\sin^2 A} = 1\\\ \\ \cos^2 A = \sin^4 A  

    cos2A=(1cos2A)2cos2A=1+cos4A2cos2A1=cos4A3cos2A\cos^2 A = (1 - \cos^2 A)^2\\\cos^2 A = 1 + \cos^4 A - 2\cos^2 A\\-1 = \cos^4 A - 3\cos^2 A\\




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