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If A and B together can do a piece of work in 20 days, and A alone can do the same work in 30 days, then in how many days can B alone complete the sam
Question

If A and B together can do a piece of work in 20 days, and A alone can do the same work in 30 days, then in how many days can B alone complete the same work?

A.

45

B.

40

C.

60

D.

50

Correct option is C

Given:  
Time take by A and B together can do a piece of work = 20 days, 
Time take by A alone to do the same work = 30 days 
Formula Used:
Work rate of A alone:1Days taken by A \frac{1}{\text{Days taken by A}}​​​
Work rate of B alone:1Days taken by B \frac{1}{\text{Days taken by B}}​​
Work rate of A and B together: 1Days taken by A and B together\frac{1}{\text{Days taken by A and B together}}​​
1Days taken by B=1Days taken by A and B together1Days taken by A\frac{1}{\text{Days taken by B}} = \frac{1}{\text{Days taken by A and B together}} - \frac{1}{\text{Days taken by A}}  ​
Solution: 
let the time take by B is TBT_B
Now,  
Therefore, time taken by B alone to complete the work is 60 days.

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