If 11=11x/(1-x), then the value of $$(2x)^2$$​is:

Given: ​

​$$11 = \frac{11x}{1-x}$$ 

Solution: ​

​$$11 = \frac{11x}{1-x}$$ 

11(1 - x) = 11x 

11 - 11x = 11x 

11x + 11x = 11 

22x = 11 

x = $$\frac{11}{22} = \frac{1}{2}$$ 

So, the value of $$(2x)^2$$ 

putting the value of x 

​$$4\times \frac{1}{2}\times \frac{1}{2} = 1$$​​

Thus the value of $$(2x)^2$$ is 1