Find the value of  $$\frac{\sin 30^\circ 17'}{\cos 59^\circ 43'} - \frac{\csc 32^\circ}{\sec 58^\circ}$$ ?​

Correct option is C

Given:

$$\frac{\sin 30^\circ 17'}{\cos 59^\circ 43'} - \frac{\csc 32^\circ}{\sec 58^\circ}$$​​

Solution:

$$\frac{\sin 30^\circ 17'}{\cos 59^\circ 43'} - \frac{\csc 32^\circ}{\sec 58^\circ} \\\ \\= \frac{\sin 30^\circ 17'}{\cos (90^\circ - 30^\circ 17')} - \frac{\csc 32^\circ}{\sec (90^\circ - 32^\circ)} \\\ \\= \frac{\sin 30^\circ 17'}{\sin 30^\circ 17'} - \frac{\csc 32^\circ}{\csc 32^\circ} \\\ \\= 1 - 1 \\= 0$$​