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Find the value of sin(180°-θ) cos(90°-θ)-cos (180°-θ) sin (90°-θ).
Question

Find the value of sin(180°-θ) cos(90°-θ)-cos (180°-θ) sin (90°-θ).

A.

cos θ

B.

1

C.

tan θ

D.

0

Correct option is B

sin(180°-θ) cos(90°-θ)-cos (180°-θ) sin (90°-θ).
= sinθ.sinθ.-(-cosθ).cosθ
= sin²θ+cos² θ
=1

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