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    Find the value of sin(180°-θ) cos(90°-θ)-cos (180°-θ) sin (90°-θ).
    Question

    Find the value of sin(180°-θ) cos(90°-θ)-cos (180°-θ) sin (90°-θ).

    A.

    cos θ

    B.

    1

    C.

    tan θ

    D.

    0

    Correct option is B

    sin(180°-θ) cos(90°-θ)-cos (180°-θ) sin (90°-θ).
    = sinθ.sinθ.-(-cosθ).cosθ
    = sin²θ+cos² θ
    =1

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