Find the value of sin 15°.

Correct option is B

Given:

Angle = 15°

Formula Used:

sin(A - B) = sin A cos B - cos A sin B

Solution:

sin(15°) = sin(45° - 30°) = sin 45° cos 30° - cos 45° sin 30°

Substitute the known values of the trigonometric ratios:

sin 45° =$$\frac1{\sqrt2}$$= cos 45°​

$$\text{cos }30° =\frac{\sqrt3}2$$​

sin 30° = $$\frac12$$​​

sin(15°) =$$\frac{1}{\sqrt{2}} \times \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} \times \frac{1}{2}$$​​

sin(15°) =$$\frac{\sqrt{3} - 1}{2\sqrt{2}}$$​​