Find the least number which is required to be added to 2495 so that the sum is exactly divisible by 3, 4, 5 and 6.

Correct option is C

Given:

The number 2495.

Divisors: 3, 4, 5, and 6.

Concept Used:

Least Common Multiple (LCM): The least common multiple of a set of numbers is the smallest number that is divisible by all the numbers in the set.

Solution:

Prime factorization:

3 = 3

4 = 2²​

5 = 5

6 = 2 $$\times$$​3

LCM = 2²$$\times$$3$$\times$$ 5 = 60​​

2495 ÷ 60 = 41 with a remainder of 35.

Since the remainder is 35, we need to add the difference between the LCM and the remainder to make the number divisible by 60.

Number to be added = LCM - remainder = 60 - 35 = 25

Option (C) is right.