Find the height of the triangle whose base is two-thirds of its height and whose area is 363 cm²

Correct option is B

Given:
Area of triangle =363 $$cm^2$$​​
Base = 2/3 of height
Formula Used:
Area of triangle = $$\frac12$$​×b× h
Solution:
Area =363 $$cm^2$$​ = $$\frac12$$​× b × h ……(1)
Where b= $$\frac23$$​ h, putting value of b in (1)

363 = $$\frac12$$​× $$\frac23$$​ h×h
3 $$\times$$​ 363 = $$h^2$$​​
1089 = $$h^2$$​​
h=33cm