Find the HCF of $$\frac{54}9$$​, $$3\frac{ 9}{17}$$​ and $$\frac{36}{51}.$$​​

Correct option is B

Given:

To $$\frac{54}{9}$$​, $$3\frac{9}{17}$$​ and $$\frac{36}{51}$$​ 

Formula Used:

Formula of HCF of fraction

$$\text{HCF} = \frac{\text{HCF of numerators}}{\text{LCM of denominators}}$$​

Solution:

Simplify the fractions

​$$\frac{54}{9} = 6$$​​

​$$3\frac{9}{17} = \frac{60}{17}$$​​

​$$\frac{36}{51} = \frac{36 \div 3}{51 \div 3} = \frac{12}{17}$$​​

​​Numerators: The HCF of 6, 60, and 12 is 6.

Denominators: The LCM of 1, 17, and 17 is 17.

​$$\text{HCF} = \frac{6}{17}$$​​