Find the HCF of $$\frac{12}{39}$$​ and $$\frac{5}{13}$$​.

Correct option is C

Given:

HCF of $$\frac{12}{39}$$​ and $$\frac{5}{13}$$​​

Concept Used:

HCF =$$\frac{\text{HCF of numerators}}{\text{LCM of denominators}}$$​

Solution:

HCF =$$\frac{\text{HCF}(12, 5)}{\text{LCM}(39, 13)}$$​

HCF(12, 5) = 1

LCM(39, 13) = 39 (since 13 divides 39)

HCF $$= \frac{1}{39}$$​