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Eighteen years ago, a man was three times as old as his son. Now, the man is twice as old as his son. The sum of the present ages of the man and his s
Question



Eighteen years ago, a man was three times as old as his son. Now, the man is twice as old as his son. The sum of the present ages of the man and his son is

A.

72

B.

100

C.

105

D.

108

Correct option is D

Let the present age of the son be x.
According to question
The present age of the man = 2x.
2x - 18 = 3(x - 18)
2x - 18 = 3x - 54
x = 36
the present age of the son = 36.
The present age of the man = 2x, or 2 × 36 = 72.
The sum of their present ages = 36 + 72 = 108.

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