A ship is approaching towards a shore. When it is 32 miles from the shore, a plane having speed 15 times that of the ship is sent to deliver supplies. How far from the seashore does the seaplane catch up with the ship?

Correct option is A

Given:
The ship is 32 miles away from the shore.
A seaplane is sent from the shore to catch the ship.
The plane's speed is 15 times the speed of the ship.
Both are moving toward each other. 
Formula Used:
Distance = Speed × Time
Solution:
Let the speed of the ship be s
Then, the speed of the plane is 15s
Let the time taken to meet be t hours
The ship travels s × t miles
The plane travels 15s × t miles
Together, the distance they cover is equal to 32 miles:
s × t + 15s × t = 32
16s × t = 32
t = $$\frac{32}{16s} = \frac{2}{s}$$​​
Now, distance traveled by the plane = Speed × Time = 15s × $$\frac 2s$$​ = 30 miles