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    The cost price of two articles is the same. One of them is sold at a profit of 13% while the other one is sold at a profit of 19%. If the difference b
    Question



    The cost price of two articles is the same. One of them is sold at a profit of 13% while the other one is sold at a profit of 19%. If the difference between their selling prices is Rs. 126, the cost price of each article is:

    A.

    Rs. 1800

    B.

    Rs. 1900

    C.

    Rs. 2000

    D.

    Rs. 2100

    Correct option is D

    Given:
    The cost of two articles is the same
    One article is sold at 13% profit
    Other article is sold at 19% profit
    Difference between their selling prices is Rs. 126
    Formula Used:
    SP=(100+P%100)×CP\text{SP} = \left( \frac{100 + P\%}{100} \right) \times \text{CP}​​
    where,
    SP = Selling Price
    CP = Cost Price
    P% = Profit Percentage
    Solution:
    Let the cost price of two articles be Rs. x
    Since, we know that selling price = (100+P%100)×CP \left( \frac{100 + P\%}{100} \right) \times \text{CP}​​
    => Selling price of first article = x × (100 + 13)%
    => Selling price of first article = 1.13x
    Selling price of second article = x × (100 + 19)%
    => Selling price of second article = 1.19x
    Now, according to question
    The difference between their selling prices = Rs. 126
    => 1.19x – 1.13x = 126
    => 0.06x = 126
    => x = 1260.06\frac{126}{0.06}​ = 2100
    ∴ The cost price of each article is Rs. 2100.

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