Chetan travels from City A to City B. If Chetan drives his car at 3/4 of his normal speed, then he reaches City B 33 minutes late. Find the time (in minutes) that Chetan would have taken to travel from City A to City B if he drove at his normal speed.

Correct option is C

Given:

- New speed = 3/4 of normal speed

- Delay = 33 minutes

- Let normal time = x minutes

Formula Used:

- Time ∝ 1 / Speed (when distance is constant)

- New time = (4/3) × original time (since speed is 3/4 of normal)

- Delay = New time - Original time

Solution:

Let normal time be x minutes.

Then new time = $$(\frac{4}{3}) × x$$​​

According to the question:

​$$(\frac{4}{3})x − x = 33\\\ \\=> \frac{(4x − 3x)}{3 }= 33 => \frac{x}{3} = 33 => x = 99$$​​

Final Answer: 99 minutes