Chetan travels from City A to City B. If Chetan drives his car at $$\frac{2}{3}$$​ of his normal speed, then he reaches City B 46 minutes late. Find the time (in minutes) that Chetan would have taken to travel from City A to City B if he drove at his normal speed.​

Correct option is A

Given:

Chetan reaches 46 minutes late when driving at $$\frac{2}{3}$$​ of his normal speed.

Concept Used:

Time is inversely proportional to speed.

Solution:

Let the normal time taken be x minutes. 

If speed is reduced to $$\frac{2}{3}$$​, time increases by $$\frac{3}{2}$$​ times.

Extra time due to reduced speed = $$\frac{3}{2}x - x = \frac{1}{2}x$$​​

​$$\frac{1}{2}x = 46$$​​

x = $$46 \times 2$$​ = 92

Chetan would have taken 92 minutes at his normal speed.