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Arrange the correlation coefficients computed from the following information on covariance i.e., cov (x, y) and standard deviations ( and ), in increa
Question



Arrange the correlation coefficients computed from the following information on covariance i.e., cov (x, y) and standard deviations ( and ), in increasing order:
(A) cov(x, y) = 18, σx = 4, σy = 9
(B) cov(x, y) = 15, σx = 8, σy = 3
(C) cov(x, y) = 16, σx = 7, σy = 4
(D) cov(x, y) = 21, σx = 6, σy = 5
Choose the most appropriate answer from the options given below:

A.

(A), (C), (B), (D)

B.

(B), (C), (D), (A)

C.

(C), (B), (A), (D)

D.

(D), (B), (A), (C)

Correct option is A

Given:

We are provided with the covariance cov(x,y) and the standard deviations σx\sigma_x​ and σy\sigma_y​ for each pair of variables.

Formula Used:

The correlation coefficient r is given by the formula:

r = cov(x,y)σxσy\frac{\text{cov}(x, y)}{\sigma_x \sigma_y}​​

Solution:

For (A):

rA=184×9=1836=0.5r_A = \frac{18}{4 \times 9} = \frac{18}{36} = 0.5​​

For (B):

rB=158×3=1524=0.625r_B = \frac{15}{8 \times 3} = \frac{15}{24} = 0.625​​

For (C):

rC=167×4=1628=0.5714r_C = \frac{16}{7 \times 4} = \frac{16}{28} = 0.5714​​

For (D):

rD=216×5=2130=0.7r_D = \frac{21}{6 \times 5} = \frac{21}{30} = 0.7​​

Arranging in increasing order:

rA=0.5, rC=0.5714, rB=0.625, rD=0.7r_A = 0.5, \, r_C = 0.5714, \, r_B = 0.625, \, r_D = 0.7​​
Thus, The correct option is (a) (A), (C), (B), (D).

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