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    Anil started his journey in the morning. Till 10 a.m., he covered12\frac 1221​​ of his journey, and on the same day till 1 a.m. be covered 45\frac 455
    Question

    Anil started his journey in the morning. Till 10 a.m., he covered12\frac 12​ of his journey, and on the same day till 1 a.m. be covered 45\frac 45​ of his journey. At what time did he start his journey?

    A.

    2.00 a.m.

    B.

    4.00 a.m.

    C.

    5.00 a.m.

    D.

    3.30 a.m.

    Correct option is C

    Given:
    Anil covered 12\frac 12​of his journey till 10 a.m.
    He covered 45\frac 45​ of his journey till 1 p.m. (not a.m., since journey continues same day).
    Solution:
    Journey covered between 10 a.m. and 1 p.m. = 4512=8510=310\frac{4}{5} - \frac{1}{2} = \frac{8 - 5}{10} = \frac{3}{10}​ of journey.
    Time taken for 310 \frac{3}{10}​ journey = 3 hours.
    Time for whole journey =(1÷310)×3=(103)×3\left( 1 \div \tfrac{3}{10} \right) \times 3 = \left( \tfrac{10}{3} \right) \times 3 = 10 hours.
    He had completed 12\frac 12​ journey by 10 a.m. => Time for 12\frac 12​ journey = 102\frac {10}2​ = 5 hours.
    So, he started at 10 a.m. – 5 hours = 5 a.m.

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