Correct option is A
Given:
Amit can complete a piece of work in 15 days.
Balbir can complete the same work in 10 days.
Formula Used:
work done = number of days efficiency
Solution:
let total work = 30 units
we take work done is 40 because of 40 is the LCM of 15,10 .
efficiency of Amit= total work done \ time in which he do it
=30\15
=2 unit
efficiency of Balbir = total work done \ time in which he do it
=30\10
=3
Amit complete the work in 3 days = number of days efficiency
=3 2
=6 unit
work remaining = 30 -6 = 24 units
so Amit and Balbir complete the all work in = total work \ efficiency
= 24\5
=4 days