Advait has to reach Kanpur which is 947 km away in 19 hours. His starting speed for 6 hours was 38 km/hr. For the next 70 km his speed was 35km/hr. By what speed he must travel now so as to reach Kanpur in decided time of 19 hours?

Correct option is D

Given:

Total distance = 947 km

Total time = 19 hours

First part: 6 hours at 38 km/hr

Second part: 70 km at 35 km/hr

Formula Used:

Distance = Speed × Time

Solution:

First part distance = 6 × 38 = 228 km

Second part distance = 70 km

Total covered = 228 + 70 = 298 km

Remaining distance = 947 - 298 = 649 km

Time taken for first part = 6 hours

Time for second part = $$\frac{70} { 35}$$​ = 2 hours

Total time used = 6 + 2 = 8 hours

Remaining time = 19 - 8 = 11 hours

Required Speed =$$\frac{ 649} { 11}$$ = 59 km/hr