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    A train P leaves Mumbai at 6:00 am and reaches Nagpur at 9:00 am. Another train leaves Nagpur at 7:00 am and reaches Mumbai at 9:00 am. At what time b
    Question

    A train P leaves Mumbai at 6:00 am and reaches Nagpur at 9:00 am. Another train leaves Nagpur at 7:00 am and reaches Mumbai at 9:00 am. At what time both the trains cross each other?

    A.

    7:54 AM

    B.

    8:15 AM

    C.

    7:48 AM

    D.

    8:12 AM

    Correct option is C


    Given:
    Time taken by train to reach Nagpur from Mumbai = 3 h
    Time taken by another train to reach Mumbai from Nagpur = 2 h
    Formula used:
    Time = Distance/Speed
    Concept Used:
    Relative Speed = Speed of one object with respect to other object
    If two object of Speed V1 and V2, respectively travels in opposite direction, Relative Speed = |V1 + V2|
    Solution:
    Let Total distance between Nagpur and Mumbai be x km
    Speed of first train = (x/3) km/h
    Speed of second train = (x/2) km/h
    First train left 1 h earlier, so distance travelled in 3 h = x/3 × 1 = x/3 km
    Now, Distance between the trains = x – x/3 = 2x/3
    Relative speed = x/3 + x/2 = 5x/6 km/h
    Time taken to meet = (2x/3)/(5x/6) = (4/5) in hour
    In min, (4/5)× 60 = 48 min
    ∴ Trains will meet at 7:48 am.

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