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    A train is moving in from north to south direction. It overtakes Raj and Madhur who are walking in the same direction at the rate of 2 km/h and 4 km/h
    Question

    A train is moving in from north to south direction. It overtakes Raj and Madhur who are walking in the same direction at the rate of 2 km/h and 4 km/h in 9 sec and 10 sec, respectively. If the train is x meters long, find the value of x.

    A.

    90

    B.

    30

    C.

    50

    D.

    70

    Correct option is C

    Given:

    Walking speeds: 2 km/h,4 km/h2 \, \text{km/h}, 4 \, \text{km/h}

    Times: 9 sec,10 sec.9 \,\text{sec}, 10 \, \text{sec}.

    Formula Used:

    Relative speed = (Train speedWalking speed)×10003600(\text{Train speed} - \text{Walking speed}) \times \frac{1000}{3600}

    Train's length: 

    x=Relative speed×Timex = \text{Relative speed} \times \text{Time}

    Solution:
    For first person:

    x=(v2)×10003600×9x = \left( v - 2 \right) \times \frac{1000}{3600} \times 9​​

    For second person:

    x=(v4)×10003600×10x = \left( v - 4 \right) \times \frac{1000}{3600} \times 10​​

    Equating the equation and simplifying:

    9(v2)=10(v4) =>v=22 km/h9(v - 2) = 10(v - 4) \\ \ \\ \Rightarrow \quad v = 22 \, \text{km/h} 

    Now, Finding x:

    x=(222)×10003600×9=50 metersx = \left( 22 - 2 \right) \times \frac{1000}{3600} \times 9 = 50 \, \text{meters}

    Thus, the train length is 50 meters.

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