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    A train crosses a man on a platform in 10 s and crosses the platform of 260 m in length in 20 s. What is the length of the train?
    Question

    A train crosses a man on a platform in 10 s and crosses the platform of 260 m in length in 20 s. What is the length of the train?

    A.

    280 m

    B.

    240 m

    C.

    220 m

    D.

    260 m

    Correct option is D

    Given:

    Time to cross a man = 10 seconds

    Time to cross a platform (260 m) = 20 seconds

    We are to find the length of the train

    Formula Used:

    Speed = distancetime \frac{distance}{time}​​

    Solution:

    Let the length of the train = L meters
    Speed of train =L10 \frac{L}{10} ​m/s

    Then, for crossing platform:

    L+26020=L10\frac{L + 260}{20} = \frac{L}{10}​​

    L + 260 = 2L

    260 = 2L - L = L

    L = 260 m

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