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​A student plots three graphs for I against V for three Ohmic conductors A, B and C. he found that the slope of these three graphs are 0.5, 0.1 and 0.
Question

​A student plots three graphs for I against V for three Ohmic conductors A, B and C. he found that the slope of these three graphs are 0.5, 0.1 and 0.2, respectively. If the conductors have the same length and their cross – section areas are in the ratio 1 : 2 : 3, then their resistivity rations i.e. ρA: ρδ: ρCwill be: ​

A.

3 : 20 : 15

B.

​1 : 20 : 15​

C.

​2 : 20 : 15​

D.

​4 : 20 : 15​

Correct option is C

The correct answer is (C) ​2 : 20 : 15​.

Understanding the Relationship

  • Ohm's Law: For an Ohmic conductor, the relationship between current (I) and voltage (V) is linear, given by: V = IR where R is the resistance of the conductor.
  • Slope of the Graph: In the I-V graph, the slope represents the reciprocal of the resistance (1/R).
  • Resistivity (ρ): Resistivity is an intrinsic property of a material, related to its resistance by: R=ρ(LA)R = ρ(\frac{L}{A}) ​where L is the length and A is the cross-sectional area.

Given Information:

  • Slopes of the graphs: 0.5, 0.1, and 0.2
  • Cross-sectional areas: 1:2:3
  • Length: Same for all conductors

Calculations:

Calculate Resistance:

ResistanceofA:10.5=2Resistance of A:\frac{1}{0.5}=2

ResistanceofB:10.1=10Resistance of B: \frac{1}{0.1}=10

ResistanceofC:10.2=5Resistance of C:\frac{1}{0.2}=5

Calculate Resistivity:

Since the length is the same for all conductors, we can use the simplified formula:ρ=R×Aρ={R}\times{A}

ResistanceofA:2×1=2Resistance of A: {2}\times{1}=2

ResistanceofB:10×2=20Resistance of B: {10}\times{2}={20}

ResistanceofC:5×3=15Resistance of C:{5}\times{3}=15

Determine Resistivity Ratios:

ρA:ρB:ρC=2:20:15ρA: ρB: ρC={2}:{20}:{15}

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