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    ​A student plots three graphs for I against V for three Ohmic conductors A, B and C. he found that the slope of these three graphs are 0.5, 0.1 and 0.
    Question

    ​A student plots three graphs for I against V for three Ohmic conductors A, B and C. he found that the slope of these three graphs are 0.5, 0.1 and 0.2, respectively. If the conductors have the same length and their cross – section areas are in the ratio 1 : 2 : 3, then their resistivity rations i.e. ρA: ρδ: ρCwill be: ​

    A.

    3 : 20 : 15

    B.

    ​1 : 20 : 15​

    C.

    ​2 : 20 : 15​

    D.

    ​4 : 20 : 15​

    Correct option is C

    The correct answer is (C) ​2 : 20 : 15​.

    Understanding the Relationship

    • Ohm's Law: For an Ohmic conductor, the relationship between current (I) and voltage (V) is linear, given by: V = IR where R is the resistance of the conductor.
    • Slope of the Graph: In the I-V graph, the slope represents the reciprocal of the resistance (1/R).
    • Resistivity (ρ): Resistivity is an intrinsic property of a material, related to its resistance by: R=ρ(LA)R = ρ(\frac{L}{A}) ​where L is the length and A is the cross-sectional area.

    Given Information:

    • Slopes of the graphs: 0.5, 0.1, and 0.2
    • Cross-sectional areas: 1:2:3
    • Length: Same for all conductors

    Calculations:

    Calculate Resistance:

    ResistanceofA:10.5=2Resistance of A:\frac{1}{0.5}=2

    ResistanceofB:10.1=10Resistance of B: \frac{1}{0.1}=10

    ResistanceofC:10.2=5Resistance of C:\frac{1}{0.2}=5

    Calculate Resistivity:

    Since the length is the same for all conductors, we can use the simplified formula:ρ=R×Aρ={R}\times{A}

    ResistanceofA:2×1=2Resistance of A: {2}\times{1}=2

    ResistanceofB:10×2=20Resistance of B: {10}\times{2}={20}

    ResistanceofC:5×3=15Resistance of C:{5}\times{3}=15

    Determine Resistivity Ratios:

    ρA:ρB:ρC=2:20:15ρA: ρB: ρC={2}:{20}:{15}

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