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A student goes to school at a speed of 20 km/h and reaches 6 min late. If he goes at a speed of 30 km/h, he is 6 min early. What is the distance to th
Question

A student goes to school at a speed of 20 km/h and reaches 6 min late. If he goes at a speed of 30 km/h, he is 6 min early. What is the distance to the school?

A.

17km

B.

16km

C.

12km

D.

​18km​

Correct option is C

Given:

Speed when student reaches 6 min late = 20km/hr

Speed when student reaches 6min early = 30km/hr

Formula Used:

Distance=Speed×TimeSpeed \times Time​​

Solution:

Let the time taken to reach school when student goes at 20km/hr be t

Then

​20×t=30×(t−1260)20\times t = 30 \times (t-\frac{12}{60}) ​      (Distnace is constsant)

​20×t=30×(t−15)20\times t = 30 \times (t-\frac{1}{5})​​

​20×t=30×(5t−15)20\times t = 30 \times (\frac{5t -1}{5})​​

​20×t=6×(5t−1)20\times t = 6 \times (5t -1)​​

​20t=30t−620t = 30t - 6​

​10t=610t= 6​​

​t=610hrt= \frac{6}{10}hr​

​Distance=20×610=12kmDistance = 20\times \frac{6}{10} = 12km​​

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