A person can complete a journey in 9 hours. He covers the first one-third part of the journey at the rate of 35 km/h and the remaining distance at the rate of 28 km/h. What is the total distance (in km) of his journey?

Correct option is C

Given:

Total time = 9 hours

Speed for first one-third = 35 km/h

Speed for remaining two-thirds = 28 km/h

Formula Used:

Distance = Speed × Time

Solution:

Let total distance be D km

From the condition;

​$$\frac{D}{3 \times 35} + \frac{2D}{3 \times 28} = 9$$​​

​$$\frac{D}{105} + \frac{2D}{84} = 9$$​​

​$$\frac{4D}{420} + \frac{10D}{420} = 9$$​​

​$$\frac{14D}{420} = 9$$​​

​$$\frac{D}{30} = 9$$​​

D = 270

Therefore, Total distance = 270 km.