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    A person can complete a journey in 13 hours. He covers the first one-third part of the journey at the rate of 24 km/h and the remaining distance
    Question

    A person can complete a journey in 13 hours. He covers the first one-third part of the journey at the rate of 24 km/h and the remaining distance at the rate of 60 km/h. What is the total distance of his journey?

    A.

    525 km

    B.

    516 km

    C.

    513 km

    D.

    520 km

    Correct option is D

    Given:

    Total time for the journey = 13 hours

    Speed for the first one-third of the journey = 24 km/h

    Speed for the remaining two-thirds of the journey = 60 km/h

    Formula Used:

    Time =Distance  Speed \frac{\text{Distance }}{\text{ Speed}}​​

    Solution:
    Let the total distance be D km.

    For the first one-third of the journey, the distance is D3.\frac{D}{3}.​​
    The time taken for the first part of the journey =D324=D72 \frac{\frac{D}{3}}{24} = \frac{D}{72}​ hours.

    For the remaining two-thirds of the journey, the distance is 2D3.\frac{2D}{3}.​​
    The time taken for the remaining part of the journey =2D360=2D180 \frac{\frac{2D}{3}}{60} = \frac{2D}{180}​ hours.

    The total time for the journey is the sum of the time for both parts:

    D72+2D180=13 5D360+4D360=13 9D360=13 9D=13×360 D=46809=520 km\frac{D}{72} + \frac{2D}{180} = 13 \\ \ \\\frac{5D}{360} + \frac{4D}{360} = 13 \\ \ \\\frac{9D}{360} = 13 \\ \ \\9D = 13 \times 360 \\ \ \\D = \frac{4680}{9} = 520 \, \text{km}

    Thus, the total distance of the journey is 520 km.

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