arrow
arrow
arrow
A part of the journey is covered in 22.5 minutes at a speed of 68 km/h and the remaining part in 12 minutes at a speed of 72 km/h. The total distance
Question

A part of the journey is covered in 22.5 minutes at a speed of 68 km/h and the remaining part in 12 minutes at a speed of 72 km/h. The total distance of the journey is (to the nearest integer):

A.

40 km

B.

38 km

C.

42 km

D.

35 km

Correct option is A

Given:
Speed in first part of journey =68km/hr
Time taken in first = 22.5min = 22.560=38\frac{22.5}{60}= \frac{3}{8}​ hr
Speed in second part of journey =72km/hr
Time taken in first = 12min = 1260=15hr\frac{12}{60}= \frac{1}{5} hr​​
Formula Used:
Distance = Speed × Time
Solution:
Distance in first part = 68×38=25.568 ×\frac{3}{8} = 25.5​km
Distance in second part = 72×1572 ×\frac{1}{5 }​= 14.4km
Total distance = 25.5+14.4 = 39.9km ≈ 40km

Free Tests

Free
Must Attempt

SSC GD PYP (Held on 4 Feb 2025 S1)

languageIcon English
  • pdpQsnIcon80 Questions
  • pdpsheetsIcon160 Marks
  • timerIcon60 Mins
languageIcon English
Free
Must Attempt

Hindi Section Test 1

languageIcon English
  • pdpQsnIcon20 Questions
  • pdpsheetsIcon40 Marks
  • timerIcon12 Mins
languageIcon English
Free
Must Attempt

SSC CGL T-I Similar Paper (Held on 12 Sep 2025 S2)

languageIcon English
  • pdpQsnIcon100 Questions
  • pdpsheetsIcon200 Marks
  • timerIcon60 Mins
languageIcon English

Similar Questions

test-prime-package

Access ‘SSC CHSL Tier I’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
389k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow