A mixture contains milk and water in the ratio 2 : 1. The total quantity of the mixture is 30 liters. If x liters of water are added to the mixture, the ratio of milk to water becomes 2 : 3. Find the value of x.

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Information Given in the Question:
Initial ratio of milk to water = 2 : 1
Total quantity of mixture = 30 liters
Water added = x liters
New ratio of milk to water = 2 : 3
Detailed Explanation:
Milk = $$\frac{2}{3}$$​×30=20liters

Water =$$\frac{1}{3}$$​×30=10liters
Water added = x liters So, new water quantity = 10+x liters
According to the question,
$$\frac{20}{10 + x} = \frac{2}{3}$$​

3 × 20 = 2 × (10 + x)
=>60 = 20 + 2x

60 – 20 = 2x
40 = 2x
x=20