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    A tank holds 5345\frac{3}{4}543​ liters of water. If 2.375 liters are drained twice, how much water remains?​
    Question

    A tank holds 5345\frac{3}{4} liters of water. If 2.375 liters are drained twice, how much water remains?​

    A.

    1

    B.

    1141\frac{1}{4}​​

    C.

    1381\frac{3}{8}​​

    D.

    1121\frac{1}{2}​​

    Correct option is A

    Given :

    A tank holds 534\dfrac{3}{4}​ liters of water.
    Amount drained each time = 2.375 liters.
    Water is drained twice.

    Solution :

    Convert mixed fraction to decimal:
    534=5.75 liters5 \dfrac{3}{4} = 5.75 \text{ liters}​​

    Total water drained:
    2.375×2=4.75 liters5 \times 2 = 4.75 \text{ liters}​​

    Water remaining:
    5.75 - 4.75 = 1.00 liter

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