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A tank holds 5345\frac{3}{4}543​ liters of water. If 2.375 liters are drained twice, how much water remains?​
Question

A tank holds 5345\frac{3}{4} liters of water. If 2.375 liters are drained twice, how much water remains?​

A.

1

B.

1141\frac{1}{4}​​

C.

1381\frac{3}{8}​​

D.

1121\frac{1}{2}​​

Correct option is A

Given :

A tank holds 534\dfrac{3}{4}​ liters of water.
Amount drained each time = 2.375 liters.
Water is drained twice.

Solution :

Convert mixed fraction to decimal:
534=5.75 liters5 \dfrac{3}{4} = 5.75 \text{ liters}​​

Total water drained:
2.375×2=4.75 liters5 \times 2 = 4.75 \text{ liters}​​

Water remaining:
5.75 - 4.75 = 1.00 liter

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