A man starts his journey at 01:00 hrs local time to reach another country at 09:00 hrs local time on the same date. Неstarts a return journey on the same night at 21:00 hrs local time, taking the same time to travel back to his original place. If the time zone of his country of visit lags by 10 hours, the duration for which the man was away from his place is

Correct option is A

Given:

• Start time: 01:00 hrs (origin local time)
• Arrival time: 09:00 hrs (destination local time)
• Time zone lag: Destination is 10 hours behind the origin
• Return starts: 21:00 hrs (destination time) on the same night
• Travel time (return) is same as onward journey

Solution:

Step 1: Calculate actual travel time
Arrival at destination: 09:00 hrs (destination time)
Convert to origin time: 09:00 + 10:00 = 19:00 hrs (same day)

Start time: 01:00 hrs (origin time)
Travel duration = 19:00 – 01:00 = 18 hours

Step 2: Return journey starts at 21:00 hrs (destination time)
Convert to origin time: 21:00 + 10:00 = 07:00 hrs next day

Add 18 hours travel back:
07:00 + 18:00 = 01:00 hrs (next to next day)

So, he reaches back at 01:00 hrs on Day 3
He started at 01:00 hrs on Day 1

Total duration away from home = 48 hours

Correct Option: (A) 48 hours